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Name: _______________________

Mr. Miller

Specific Heat – Problems

Q = cm∆t, where:
Q = heat energy in calories
c = specific heat capacity (water is defined as 1 cal/g°C)
m = mass in grams
∆t = change in temperature in degrees Celsius

Also note: 1 kg (kilogram) = 1000 grams = 2.2 pounds

  1. A hot potato is put into a cold glass of 20°C water.  After the potato and the water have come to a common temperature, the thermometer reading of the water is found to be 23°C.  Knowing the mass of the water to be 250 grams, find the amount of heat Q received by it.





  1. 3,000 calories of energy are added to 500 grams of water that originally has a temperature of 40°C.  What will be the final temperature of the water?






  1. The sun shines on a small 300 liter (which is the same as 300 kilograms) pool of water all day long until the temperature of the pool goes from 20°C in the morning to 35°C in the evening.  How much heat energy did the sun give to the water in the pool?





  1. A very hot chunk of concrete at 500°C that weighs 800 grams is dropped into a bucket containing 3 liters of water.  The final temperature of the water and the concrete is 98°C.  The specific heat of concrete is 0.72 cal/g°C.  How much does the temperature of the water increase?  (Hint: first find out how much heat the chunk of concrete loses to the water, then calculate how much that heat changes the temperature of the water.)



specific heat problems